2x^2+12x+26=8

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Solution for 2x^2+12x+26=8 equation: 



2x^2+12x+26=8

We move all terms to the left:

2x^2+12x+26-(8)=0

We add all the numbers together, and all the variables

2x^2+12x+18=0

a = 2; b = 12; c = +18;
Δ = b2-4ac
Δ = 122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{4}=-3$

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